[problem]
Ever needed to print out one column with awk, but do not know the field number?
[/problem]
[solution]
Here I’m running df and looking for a field with “Used” in it:
df -k | head -1 | awk ' {
for(i=1; i< NF;i++) {
if($i ~ /Used/) {
print "# field "i
}
}
} '
So stop counting columns and just use the code! 🙂
[/solution]
[example]
Now for a real life demo. 😉
[[email protected] marcus]$ df -k | head -1
Filesystem 1K-blocks Used Available Use% Mounted on
[[email protected] marcus]$ df -k | awk ' {
for(i=1;i < NF;i++) {
if($i ~ /Used/) { print "# field "i }
}
} '
# field 3
[/example]
[reference]
[tags], Unix Coding School[/tags]
[/reference]
If you have found my website useful, please consider buying me a coffee below 😉
I have to search a string like Annual Income, which has a space. How do we handle this.
Thank you,
Rama
Hi Rama, if you wanted to split out by column – but ignore Annual Income, then perhaps use sed and pipe through awk. Like this sed 's/Annual Income/Annual-Income/g' filename | awk ….