Sample code for working with Python Dicts
# init users list of dicts, print out id 1, then init friends list of tuples
users = [
{ "id": 0, "name": "Bob" },
{ "id": 1, "name": "Dunn" },
{ "id": 2, "name": "Sue" },
{ "id": 3, "name": "Chi" },
{ "id": 4, "name": "Thor" },
{ "id": 5, "name": "Clive" },
{ "id": 6, "name": "Hicks" },
{ "id": 7, "name": "Devin" },
{ "id": 8, "name": "Kate" },
{ "id": 9, "name": "Klein" },
{ "id": 10, "name": "Jen" } ]
i=0
for user in users:
if(users[i]["name"]=="Bob"):
print("Bob ID: ",users[i]["id"])
i+=1
friends= [(0, 1), (0, 2), (1, 2), (1, 3), (2, 3), (3, 4), (4, 5), (5, 6), (5, 7), (6, 8), (7, 8), (8, 9)]
# spin through all users and create empty list to store list, then populate
for user in users:
user["friends"]=[]
# populate empty list with all left side of tuple with right and vice versa
for i,j in friends:
users[i]["friends"].append(users[j])
users[j]["friends"].append(users[i])
# function to return length based on passed in user
def number_of_friends(user):
"""how many friends does _user_ have?"""
return len(user["friends"]) # length of friend_ids list
# total up all friends
total_connection = sum(number_of_friends(user)
for user in users) # 24
# grab number of users
num_users = len(users)
avg_connections = total_connection / num_users # 2.4
# create a list (user_id, number_of_friends)
num_friends_by_id = [(user["id"], number_of_friends(user)) for user in users]
print(sorted(num_friends_by_id,key=lambda pair: pair[1], reverse=True))
# Output – largest to smallest
[(1, 3), (2, 3), (3, 3), (5, 3), (8, 3), (0, 2), (4, 2), (6, 2), (7, 2), (9, 1), (10, 0)]
